Chem 3.9

research 1 (Multiple Choice worth(predicate) 3 points) Which of the following(a) pairs sh are the comparable falsifiable face?  CH4 and C2H4  PbCl2 and PbCl4  N2O5 and NO2  CH2O and C6H12O6 Question 2 (Multiple Choice worthy 3 points) How many moles of oxygen are in 1 mole of Fe(NO3)3?  2  3  6  9 Question 3 (Essay Worth 5 points) A compound that is still of atomic number 42 (Mo) and oxygen (O) was produced in a lab by heating minute over a Bunsen burner. The following data was lay in: jackpot of crucible: 38.26 g Mass of crucible and minute: 39.52 g Mass of crucible and molybdenum oxide: 39.84 g Solve for the empirical formula of the compound, exhibit (or explaining in complete sentences) your calculations. To engender the jalopy of molybdenum in the crucible, you subtract the volume of the crucible from the great deal of the crucible and molybdenum: 39.52g - 38.26g = 1.26g To bugger off hold the deal of molybdenum ox ide in the crucible, you subtract the jalopy of the crucible from the wad of the crucible and molybdenum oxide: 39.84g - 38.26g = 1.58g To regain the chain reactor of oxide, you subtract the skunk of molybdenum from the hatful of molybdenum oxide: 1.58g - 1.26g = 0.32g To get the number of moles of molybdenum you discriminate the mass of molybdenum by its molecular mass: 1.26g/96 = 0.

01 moles To get the number of moles of oxide, basin the mass of oxide by its molecular mass: 0.32g/16 = 0.02 moles thither are double as many moles of oxygen so the empirical formula is: MoO2 39.52g - 38.26g = 1.26g To get the mass of molybdenum oxide in the crucible, you subtract the mass of the cru cible from the mass of the crucible and moly! bdenum oxide: 39.84g - 38.26g = 1.58g To get the mass of oxide, you subtract the mass of molybdenum from the mass of molybdenum oxide: 1.58g - 1.26g = 0.32g To get the number of moles of molybdenum you divide the mass of molybdenum by its molecular mass: 1.26g/96 = 0.01 moles To get the number of moles of oxide, divide the mass of oxide by its molecular...If you want to get a near essay, order it on our website: OrderEssay.net

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